50=10x^2/5

Solution for 50=10x^2/5 equation:

50=10x^2/5

We move all terms to the left:

50-(10x^2/5)=0

We get rid of parentheses

-10x^2/5+50=0

We multiply all the terms by the denominator


-10x^2+50*5=0

We add all the numbers together, and all the variables

-10x^2+250=0

a = -10; b = 0; c = +250;
Δ = b2-4ac
Δ = 02-4·(-10)·250
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*-10}=\frac{-100}{-20}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*-10}=\frac{100}{-20}
=-5
$